Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Three different vectors satisfy the relations
and
, then either
is….. to
or
is …….. with
.
Text Solution
Verified by ExpertsThe correct answer is:
C
To determine the relationship among the vectors \\( \vec{A}, \vec{B}, \vec{C} \\), we use the given conditions:
1. \\( \vec{A} \. \vec{B} = 0 \\): This implies \( \vec{A} \\) and \( \vec{B} \\) are perpendicular.
2. \\( \vec{A} \. \vec{C} = 0 \\: This implies \( \vec{A} \\) and \( \vec{C} \\) are also perpendicular.
Given both conditions, \( \vec{A} \\) is orthogonal to both \( \vec{B} \\) and \( \vec{C} \\. Therefore, the vectors \( \vec{B} \\) and \( \vec{C} \\) must be in the same plane, with \( \vec{A} \\) normal to that plane. This leads to the conclusion that \( \vec{B} \\) must be perpendicular to \( \vec{C} \\: \vec{B} \times \vec{C} \\$ is a vector perpendicular to both, thus satisfying the conditions. Hence, the answer is option C.
1. \\( \vec{A} \. \vec{B} = 0 \\): This implies \( \vec{A} \\) and \( \vec{B} \\) are perpendicular.
2. \\( \vec{A} \. \vec{C} = 0 \\: This implies \( \vec{A} \\) and \( \vec{C} \\) are also perpendicular.
Given both conditions, \( \vec{A} \\) is orthogonal to both \( \vec{B} \\) and \( \vec{C} \\. Therefore, the vectors \( \vec{B} \\) and \( \vec{C} \\) must be in the same plane, with \( \vec{A} \\) normal to that plane. This leads to the conclusion that \( \vec{B} \\) must be perpendicular to \( \vec{C} \\: \vec{B} \times \vec{C} \\$ is a vector perpendicular to both, thus satisfying the conditions. Hence, the answer is option C.
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